Helps other - Leave a rating for this single slit (see below) More Interference and Diffraction of Light Lessons and Learning Resources Optics Learning Material Tutorial IDĭoes the Diffraction of Light Wave Exist?Įnjoy the "Single Slit Diffraction Formula" physics lesson? People who liked the "Interference and Diffraction of Light lesson found the following resources useful: There are 4 lessons in this physics tutorial covering Interference and Diffraction of Light, you can access all the lessons from this tutorial below. You have reached the end of Physics lesson 12.4.2 Single Slit Diffraction Formula. Moreover, this phenomenon causes light from a coherent source to interfere with itself, which in results in creating a distinctive pattern on the screen called the diffraction pattern.As you see from the result, these light rays belong to UV spectrum. Question 2: What is meant by single-slit diffraction?Īnswer 2: In the single-slit diffraction, observance can be made of the phenomenon of bending of light or diffraction. Moreover, the central maxima is obtainable at point 0 on the screen. Furthermore, central maxima is surrounded by dark and bright lines known as the secondary minima and maxima. Question 1: What is meant by diffraction maxima and minima?Īnswer 1: The diffraction pattern involves a central bright fringe, also known as the central maxima. ⇒ Angular width of central maximum = 2θ = 2λa FAQs For Single Slit Diffraction Well, the width of the central maximum is simply twice this value Now, one may ask how to find width of central maximum. The position of the minima expressed by y (whose measurement takes place from the centre of the screen) is: Furthermore, it simply refers to the distance between the first order minima from the centre of the screen existing on both sides of the centre. The maxima lies between the minima and the width of the central maximum. Similarly, for the nth fringe, division of the slit can take place into 2n parts and this condition can be used as: As such, one can obtain a dark fringe.įor the next fringe, division of the slit can take place into 4 equal parts of a/4 and the same logic can be applied. Therefore, at θ = sin − 1λa, there would be destructive interference because any ray emanating from a point has a counterpart that produces destructive interference. Furthermore, the path difference must be out of phase by λ2, with λ being the wavelength.įor a ray emanating from any point in the slit, there exists another ray at a distance a/2 from which destructive interference can take place. Moreover, one can consider any arbitrary pair of rays at a distance a/2.įor a dark fringe, the path difference must produce destructive interference. Furthermore, it is possible to consider any number of ray pairings that start from a distance a/2 from one another. The path difference exhibited by the top two rays is:Īn important point to remember is that this calculation is valid only if D is very large. Furthermore, consider a pair of rays whose emanation takes place from distances a/2 from each other. ![]() Also, the division of the slit can take place into zones of equal widths a/2. In order to describe the pattern, one must first look at the condition for dark fringes. ![]() ![]() Now, one can identify the angular position of any point on the screen by ϑ whose measurement takes place from the slit centre which divides the slit by a/2 lengths. x`D is the separation between slit and source. Single Slit Diffraction Formula of Single Slit DiffractionĬonsider that the slit width a << D.
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